When I purchased a Solar Panel, the first asking is: Does it really can reaching out for 100Watt Dc peak?
The answer is: NO. The answer here is came from the experiment in my own home last September 2020.
FISH POND
I have a Fish Pond. The water need to circulating for making fish still life. Any bad water circulating, many losses in my fish.

25WATT WATER PUMP NEED
I use the 25Watt Electric Water Pump to make circullation in my Fish Pond. The fish need the bubble of water came from the shower fall down to the surface of the water,

I think the 25 Watt is good enough to making a bubble in the pond. But now I try to make the electrical power I used for the pump is came from the inverter 12 to 220VAC . I use an Inverter 1000W for it.
USED SEAL LEAD ACID BATTERY
For generating the Electrical Power to supply the pump, I use an used Acid Battery. Indonesian said: AKKI. 50AH is good enough to making an 25Watt DC for 24hours run. The calculationis: 12V x 50 AH = 600WH. If the load is 25W, its look like 600WH/25W = 24 running hours.
Some question: Can I use the battery lower than 50AH? The answer is : Yes you still can use it. But the running time of the battery is can not reach the 24 hours. It will be drop or run out before 24 hours.
MAXIMUM CURRENT WAS ONLY 4.38Amp at 12.00 CLOCK
Why do I choose the 100WP Solar Module? because they are could generate the amount in electricity. But, is it could be reaching the maximum result to charge the battery?
Here it is the answer. When the clock said 12.00 or the hottest sun in my country, I try to measure the output of the Solar Module. Its says 4,38 DC Amp at 13,5VDC Battery. It means the Solar Module just can generate the power as big as 4.38A x 13.5VDC = 59.13 Watt.

Ampere to Battery 
Battery Voltage
If that time is a maximum amount of DC current, so I can summarize that the peak of my Solar Module is 59WP, not 100WP.
CHARGING WHILE LOADING
If the power of Solar Module was bigger than a load, you can run your pump while your battery charged by the Solar Module. Because the water pump ony need 25WAC and your Solar Module can generate 59WDC.
Your Inverter has an Electrical Efficiency at least 80% , inverter need 25W/0.8= 31.25WDC. You still had amount 59.13 – 31.25 = 27,88WDC . Its big enough to charge the battery.
But the asking is: Is the Solar Module generate same number of Current at whole time? The answer is : NO. The 59WDC here is THE PEAK POWER of the Solar Module to generate the Electricity Power. The longer it goes to the afternoon, the less electricity that can be generated by the Solar Module.
Lets measure. The number of Ampere to load the inverter said 1,76A. It same with 1,76A x 13,5V = 23,76WDC. Then the AC Power is 23.76WDC x 0.8 = 19WAC.

Why the Power of Water Pump is smaller than the rate power said at the case or on the Box (25WAC)? Its because the pump is not run in full loading.
Charging while loading can do in your Battery if you have a big amount of Solar Module but lower in load ( AC load or DC load ).
If your solar module smaller than load, you can not run your load for long time. Otherwise, if your Solar Module is bigger than load, it can be the longer running your electrical equippment.
